Bar Bending Schedule for Footings  Steel Quantity of Footing  Estimation of Reinforcement in Footing  BBS of Rectangular Footing
In this Article today we will talk about the Bar Bending Schedule for Footings  Steel Quantity for Footings  Estimation of Reinforcement in Footing  BBS of Rectangular Footing  Steel Estimation for Footings  Footing Estimate Calculation
Bar Bending Schedule for footings:
Bar Bending Schedule plays a vital role in the construction of High rise buildings. It is very important to learn Bar Bending Schedule for finding out the quantities of Steel reinforcement required for every component of the building.
For Suppose, consider the case of high rise buildings, It requires tons of steel to complete 10+ floor building. It’s impossible to order all the steel required for whole construction at a time it creates a problem of space and also steel is prone to corrosion by the contact of water (rain). To avoid this, high rise building orders reinforcement (steel) as per requirement. Firstly they find the Estimation of Steel reinforcement in footings (steel quantities) [Bar Bending Schedule for footings], required for the construction of footings. After the completion of footings they go for next order and so on.
If you are new to Bar Bending Schedule, Refer the Basics of Bar Bending schedule
If you wanted to know different types of footings check here Different types of footings
Quantity of Reinforcement (Steel) required for footings / Bar Bending Schedule for footings:
The procedure to finding out the quantities of steel required for the footings, We are considering the below footing plan.
Observations from the above fig:
 F1, F4, F7 is Plain footing (1.0 × 1.0 × 0.8)
 F2 is Stepped Footing (0.9 × 0.9 × 1.35)
 F3, F8 is Isolated footing (0.9 × 0.9 × 0.5)
 F5 is Combined Isolated footing (4.2 × 1.7 × 0.9)
 F6 is Shoe footing (0.6 × 0.6 × 0.4)
OTHER POSTS:

Spread Footing or Isolated Footing Reinforcement Detail

What is Concrete Cover  Concrete Cover for Slab, Beam, Column, Footing

Useful Tips for Design of RCC Members  Beam, Column, Slab, Footing
Steps involved in calculating the bar bending schedule of a footings:
Remember, Steel required for construction is ordered in Kgs or Number of Bars. The standard size of each bar is 12m. The final output of BBS calculation is in Kgs or in Number of “12m” Bars. Deduct the concrete cover to find the dimensions of bars.
 Find the Length of single X Bars & Y Bars
 Find the total length of X bars. & Y bars
 Calculate the weight of steel required per 1m
 Calculate the total number of 12m bars required
 Find the total weight of steel required.
Plain footing Bar Bending schedule  F1, F4, F7
For the calculation of the total quantity of steel required for the Plain footing, we are adopting these dimensions for bars. Dimensions of Footing are 1.0 × 1.0 × 0.9 (Length × Breadth × Depth)
 Plain mesh is adopted for F1, F4, F7 footings
 Dia of X Bars is 16mm (Dia 16mm @ 100mm C/C)
 Dia of Y Bars is 12mm (Dia 12mm @ 100mm C/C)
 which means Center to center spacing between X bars & Y bars is 100mm
Length of
Each X bar 
= 0.8m 
Length of
Each Y bar 
= 0.8m 
No. of X bars  [(Y Bar Length)/Spacing]+1
= [0.8/0.1]+1 = 9bars 
No. of Y bars  [(X Bar Length)/Spacing]+1
= [0.8/0.1]+1 = 9bars 
Total Length
of X bars 
= Length of each X bar ×
No. of X Bars = 0.8 × 9 =7.2m 
Total Length
of Y bars 
= Length of each Y bar ×
No. of Y Bars = 0.8 × 9 =7.2m 
Total No. of ’12m’
X bars 
= 7.2/12
= 0.6bars 
Total No. of ’12m’
Y bars 
= 7.2/12
= 0.6bars 
Weight of steel
required for 1m of 16mm bar 
= D^{2}/162
= 16^{2}/162 = 1.58kg/m 
Total weight of
steel required for X bars 
= 1.58 × 7.2
= 11.37Kgs 
Weight of steel
required for 1m of 12mm bar 
= D^{2}/162
= 12^{2}/162 = 0.88kg/m 
Total weight of
steel required for Y bars 
= 0.88 × 7.2
= 6.33Kgs 
Isolated footings Bar Bending Schedule  F3, F8
For the calculation of the total quantity of steel required for the Isolated footing, we are adopting below dimensions for bars. Hook mesh is adopted for F3, F8 footings
 Dimensions of Footing are 0.9×0.9×0.5 (Length × Breadth × Depth)
 Dia of X Bars is 16mm (Dia 16mm @ 100mm C/C)
 Dia of Y Bars is 12mm (Dia 12mm @ 90mm C/C)
 which means Center to center spacing between X bars is 100mm & Y bars is 90mm
Length of
Each X bar 
= 0.7+2×9d
d = 16mm = 0.016m = 0.7+2×9×0.016 = 0.988m 
Length of
Each Y bar 
= 0.7+2×9d
d = 12mm = 0.012m = 0.7+2×9×0.012 = 0.916m 
No. of X bars  [(Y Bar Length)/Spacing]+1
= [0.7/0.1]+1 = 8bars (Don’t include hook length in calculating no. of bars) 
No. of Y bars  [(X Bar Length)/Spacing]+1
= [0.7/0.09]+1 = 9bars 
Total Length
of X bars 
= Length of each X bar ×
No. of X Bars = 0.988 × 8 =7.9m 
Total Length
of Y bars 
= Length of each Y bar ×
No. of Y Bars = 0.916 × 9 =8.24m 
Total No. of ’12m’
X bars 
= 7.9/12
= 0.65bars 
Total No. of ’12m’
Y bars 
= 8.24/12
= 0.68bars 
Weight of steel
required for 1m of 16mm bar 
= D^{2}/162
= 16^{2}/162 = 1.58kg/m 
Total weight of
steel required for X bars 
= 1.58 × 7.9
= 12.48Kgs 
Weight of steel
required for 1m of 12mm bar 
= D^{2}/162
= 12^{2}/162 = 0.88kg/m 
Total weight of
steel required for Y bars 
= 0.88 × 8.24
= 7.25Kgs 
Stepped footings Bar Bending Schedule  F2
For the calculation of the total quantity of steel required for the Plain footing, we are adopting these dimensions for bars. Hook mesh is adopted for F2 footings
 Dimensions of Footing are 0.9 × 0.9 × 1.35 (Length × Breadth × Depth)
 Dia of X Bars is 16mm (Dia 16mm@110mm C/C)
 Dia of Y Bars is 20mm (Dia 12mm@115mm C/C)
 which means Center to center spacing between X bars is 110mm & Y bars is 115mm
Length of
Each X bar 
= 0.7+2×9d
d = 16mm = 0.016m = 0.7+2×9×0.016 = 0.988m 
Length of
Each Y bar 
= 0.7+2×9d
d = 12mm = 0.012m = 0.7+2×9×0.020 = 1.06m 
No. of X bars  [(Y Bar Length)/Spacing]+1
= [0.7/0.11]+1 =~7bars (Don’t include hook length in calculating no. of bars) 
No. of Y bars  [(X Bar Length)/Spacing]+1
= [0.7/0.115]+1 = ~6bars 
Total Length
of X bars 
= Length of each X bar ×
No. of X Bars = 0.988 × 7 =7.9m 
Total Length
of Y bars 
= Length of each Y bar ×
No. of Y Bars = 1.06 × 6 =6.36m 
Total No. of ’12m’
X bars 
= 7.9/12
= 0.65bars 
Total No. of ’12m’
Y bars 
= 6.36/12
= 0.53bars 
Weight of steel
required for 1m of 16mm bar 
= D^{2}/162
= 16^{2}/162 = 1.58kg/m 
Total weight of
steel required for X bars 
= 1.58 × 7.9
= 12.48Kgs 
Weight of steel
required for 1m of 12mm bar 
= D^{2}/162
= 20^{2}/162 = 2.46kg/m 
Total weight of
steel required for Y bars 
= 2.46 × 6.36
= 15.64Kgs 
Eccentric/Shoe footings Bar Bending Schedule  F6
For the calculation of the total quantity of steel required for the Plain footing, we are adopting these dimensions for bars. BBS of Rectangular Footing Mesh extended till Depth of Footing is adopted for F6 footings
 Dimensions of Footing are 0.6 × 0.6 × 0.4 (Length × Breadth × Depth)
 Dia of X Bars is 16mm (Dia 16mm@80mm C/C)
 Dia of Y Bars is 16mm (Dia 16mm@80mm C/C)
 which means Center to center spacing between X bars & Y bars is 80mm
Length of
Each X bar 
= 0.4+0.3+0.3
= 1.0m 
Length of
Each Y bar 
= 0.4+0.3+0.3
= 1.0m 
No. of X bars  [(Y Bar Length)/Spacing]+1
= [0.4/0.08]+1 =~6bars (Don’t include extra bar length in calculating no. of bars) 
No. of Y bars  [(X Bar Length)/Spacing]+1
= [0.4/0.08]+1 = ~6bars 
Total Length
of X bars 
= Length of each X bar ×
No. of X Bars = 1.0 × 6 =6m 
Total Length
of Y bars 
= Length of each Y bar ×
No. of Y Bars = 1.0 × 6 =6m 
Total No. of ’12m’
X bars 
= 6/12
= 0.5bars 
Total No. of ’12m’
Y bars 
= 6./12
= 0.5bars 
Weight of steel
required for 1m of 16mm bar 
= D^{2}/162
= 16^{2}/162 = 1.58kg/m 
Total weight of
steel required for X bars 
= 1.58 × 6
= 9.48Kgs 
Weight of steel
required for 1m of 12mm bar 
= D^{2}/162
= 12^{2}/162 = 1.58kg/m 
Total weight of
steel required for Y bars 
= 1.58 × 6
= 9.48Kgs 
Combined Footing Bar Bending Schedule  F5
For the calculation of the total quantity of steel required for the combined footing, we are adopting these dimensions for bars. Steel Estimation for Footings
 Hook Mesh is usually adopted for F5 footing.
 Dimensions of Footing are 4.2 × 1.7 × 0.9 (Length × Breadth × Depth)
 Dia of X Bars is 12mm (Dia 12mm@100mm C/C)
 Dia of Y Bars is 12mm (Dia 12mm@100mm C/C)
 which means Center to center spacing between X bars & Y bars is 100mm
Length of
Each X bar 
= 4.2+2×9d
d = 12mm = 0.012m = 4+2×9×0.012 = 4.41m 
Length of
Each Y bar 
= 1.7+2×9d
d = 12mm = 0.012m = 1.7+2×9×0.012 = 1.91m 
No. of X bars  [(Y Bar Length)/Spacing]+1
= [1.7/0.1]+1 =18bars (Don’t include hook length in calculating no. of bars) 
No. of Y bars  [(X Bar Length)/Spacing]+1
= [4.2/0.1]+1 = 43bars 
Total Length
of X bars 
= Length of each X bar ×
No. of X Bars = 4.41 × 18 =79.38m 
Total Length
of Y bars 
= Length of each Y bar ×
No. of Y Bars = 1.91 × 43 =82.13m 
Total No. of ’12m’
X bars 
= 79.38/12
= 6.6bars 
Total No. of ’12m’
Y bars 
= 82.13/12
= 6.84bars 
Weight of steel
required for 1m of 16mm bar 
=D^{2}/162
=12^{2}/162 =0.88kg/m 
Total weight of
steel required for X bars 
= 0.88 × 79.38
= 69.85Kgs 
Weight of steel
required for 1m of 12mm bar 
=D^{2}/162
=12^{2}/162 =0.88kg/m 
Total weight of
steel required for Y bars 
= 0.88 ×82.13
= 72.27Kgs 